4^3-^2x=(1/8)^x(64x+1)

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Solution for 4^3-^2x=(1/8)^x(64x+1) equation: 



4^3-^2x=(1/8)^x(64x+1)

We move all terms to the left:

4^3-^2x-((1/8)^x(64x+1))=0



Domain of the equation: 8)^x(64x+1))!=0

x∈R



We add all the numbers together, and all the variables

-^2x-((+1/8)^x(64x+1))+4^3=0

We add all the numbers together, and all the variables

-^2x-((+1/8)^x(64x+1))+64=0

We multiply all the terms by the denominator


-^2x*8)^x(64x+64*8)^x(64x+1+1))-((+1))=0

We add all the numbers together, and all the variables

-^2x*8)^x(64x+512)^x(64x+2))-(1)=0

We add all the numbers together, and all the variables

-^2x*8)^x(64x+512)^x(64x=0

Wy multiply elements

8x^2+512)^x(64x=0

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